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Determination of the refractive index of thin lens

Voltammetry measurement resistor, the ammeter and voltmeter circuit even people in two ways, as shown in Figure 5 (a), (b) below. When the tested voltmeter resistance is the resistance value than the much smaller, in order to make the measurement error is small, the connection should be used is the (plant) jl 『『 - ④ _LR-LR (a) (b) State 5A. (A); B. (B); c. (A),[link widoczny dla zalogowanych], (b) optional; D. (A), (b) the rejection of a connection, averaging 7. A DC circuit, electromotive force for the clamor internal resistance r, the external circuit resistance R, For there were: (1) Road terminal voltage equal to the force; (2) the maximum current intensity in the circuit; (3) Power output power the particular case, external resistor values should be taken in order: (1 )();( 2 )();( 3) (). The answer options are as follows: AR: O; BR =; C. R =; D. ∞ & the capacitance of the capacitor, the following statements is correct () A. Capacitance is numerically equal to its capacity of electricity; B. Accommodate large capacitor power capacitor of small capacitance of the capacitor is not necessarily the kiln than the much more satisfied: C storage capacitor it is saying the power is proportional to the voltage it is saying is inversely proportional to the bipolar plates Q; D. Capacitor only with its own geometry, but not with the media between the plates has no weaknesses in 9 of the two small balls of equal mass, each with a long silk thread hanging f at the same point, two balls each with charge and 0:. And mutually exclusive, so hanging the angle between the line and the vertical direction, respectively and, the following statement is correct () A. If Q2, then; D. And Q2 values regardless of what port. And the total equal. 10. By the two parallel metal plates of the capacitor,[link widoczny dla zalogowanych], the bipolar plates a distance d, great pull horizontally connected to DC power, the two parallel plates as the potential difference between the U, there is a droplet between parallel plates, the quality of m, power is 0, just balance the static, if the power supply constantly open, the capacitor bottom plate fixed on the plates slowly move down, the oil will be () A. Upward acceleration; B. Downward acceleration; C. Stationary; D. Down uniform. Third, the calculation problems 1. An electron in a uniform electric field in the A point was 8 × 10N of the electric force, field strength of the point to ask is how much? Shan If the electric field E along the direction of the force from the A point to the 1.0 × 10 ~ m in B point, asking how much it changes the electrical potential energy? A, B two points to ask how much potential difference? 2. A rated voltage winding 220V, 1kW power rating of the heating wire, resistance rate to be 1.0 × 10n · m, cross-sectional area of 1.0x10 nickel chromium wire how long? 3. A metal wire length 0.5m. 0.01k quality differences, the same spring suspension with two magnetic induction intensity in the uniform magnetic field of 0.4T (Figure 6), when the pass to 2A current from left to right, the spring length by 3 sec. 0 × 10''m, if the pass to 0.2A of current from right to left, the spring extension number? × × × Figure 64 there is a power force to 250V,[link widoczny dla zalogowanych], resistance is 1.511,[link widoczny dla zalogowanych], and use it to a number of light 220V , 40W lamp power supply, known transmission line resistance for a total of 1.5n, to make the normal light-emitting lamp,[link widoczny dla zalogowanych], lamp light parallel number = '5. Figure 7 shows the uniform electric field in the AB = BC = cD = 4mm, negative plate grounded, the bipolar plate to ask potential difference is 120V, seeking: (1) B point potential; (2) an electron at the B point of the electric potential energy E Yang; Figure 7 (3) an electronic departure from the negative plate when the electric field force to reach the positive plate work done. A u ... one by one one by one ● ● a '... ~ ... ... ... * (Continued from page 30) with respect to different wavelengths of light and the refractive index of the same focal length lens is different, the greater the wavelength. Refractive index of smaller focal length can be seen especially in the more experimental and theoretical results are fully consistent with, and this also proved experimental method proposed in this paper is feasible in terms of the double-concave lens, its image depends on the source-oriented of that side, concave mirror reflection image can be seen and things like the location to the same, and other large inverted, then the matter will be twice the focal length in place, while the focal length is too small radius of curvature equal to half, or, = r / 2, So both sides of double-concave lens radius of curvature can be obtained directly from the experimental, calculated by the formula method was like a concentrated focal length lens, resulting in lens refractive index. Visible double-concave lens of the imaging light path than the convex lens imaging optical simpler, in this do not do a detailed analysis of the convex lens, the radius of curvature on one side can be directly measured, the other side using the above method measured; focal length is also used objects such as Formula Method may thus also the parameters of lens available